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2 bytes added ,  21:29, 8 April 2014
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<math>V_{meta,i}=\sum_{k=1}^S{V_{ii,k}}</math>
 
<math>V_{meta,i}=\sum_{k=1}^S{V_{ii,k}}</math>
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Then the score test statistics for the <math>i^{th}</math> variant <math>T_{meta,i}</math> asymptotically follows standard normal distribution  
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Then the score test statistics for the <math>i^{th}</math> variant, <math>T_{meta,i}</math>, asymptotically follows standard normal distribution  
    
<math>T_{meta,i}=U_{meta,i}\bigg/\sqrt{V_{meta,i}}=\sum_{k=1}^S {U_{i,k}}\bigg/\sqrt{\sum_{k=1}^S{V_{ii,k}}} \sim\mathbf{N}(0,1)</math>
 
<math>T_{meta,i}=U_{meta,i}\bigg/\sqrt{V_{meta,i}}=\sum_{k=1}^S {U_{i,k}}\bigg/\sqrt{\sum_{k=1}^S{V_{ii,k}}} \sim\mathbf{N}(0,1)</math>
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