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and its variance
and its variance
<math>V_{meta_i}=\sum_{k=1}^S{V_{ii,k}}</math>
<math>V_{meta_i}=\sum_{k=1}^S{V_{ii,k}}</math>.
Then the score test statistics for the <math>i^{th}</math> variant <math>T_{meta_i}</math> asymptotically follows standard normal distribution
Then the score test statistics for the <math>i^{th}</math> variant <math>T_{meta_i}</math> asymptotically follows standard normal distribution
