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It is important that the normalization results in a unique representation of the variant.  Before we begin the proof, intuitively, accept that any representation of a variant can be
 
It is important that the normalization results in a unique representation of the variant.  Before we begin the proof, intuitively, accept that any representation of a variant can be
transformed to another representation by removing or adding nucleotides from the reference sequence.
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transformed to another representation by adding nucleotides from the reference sequence to either ends of all  the alleles at the same time or removing equivalent nucleotides from the ends of
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all the alleles at the same time.  
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Now suppose there are 2 normalized variants A and B.  Suppose A is at a different position from B and B is to the right of A (without loss in generality), this is not possible because by the  definition of a normalized variant, it is left aligned,
 
Now suppose there are 2 normalized variants A and B.  Suppose A is at a different position from B and B is to the right of A (without loss in generality), this is not possible because by the  definition of a normalized variant, it is left aligned,
 
and if they were at different positions, that means B may be left aligned to A since they represent the same variants leading to a contradiction.  So A and B must be at the same position.
 
and if they were at different positions, that means B may be left aligned to A since they represent the same variants leading to a contradiction.  So A and B must be at the same position.
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Now, suppose that A and B are of different lengths where B is longer than A, then this is not possible as B is then not parsimonious, so B can be trimmed to the same length as A.
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Now, suppose that A and B are at the same position but are of different lengths where B is longer than A (without loss in generality), this is not possible as B is then not parsimonious, so B can be trimmed to the same length as A.
 +
 
    
Thus A and B have to be at the same position and have the same length and variant normalization is unique.
 
Thus A and B have to be at the same position and have the same length and variant normalization is unique.
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