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, 04:06, 23 March 2015
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| Assume that you have a set of single variant score statistics and their covariance matrices. The examplar command can be: | | Assume that you have a set of single variant score statistics and their covariance matrices. The examplar command can be: |
| | | |
− | score.stat.file<- c('study1.singlevar.assoc.gz','study1.singlevar.assoc.gz');
| + | cov.file <- c("study1.MetaCov.assoc.gz","study2.MetaCov.assoc.gz"); |
− | cov.file<- c('study1.singlevar.cov.gz','study1.singlevar.cov.gz');
| + | score.stat.file <- c("study1.MetaScore.assoc.gz","study2.MetaScore.assoc.gz") |
| | | |
| + | res <- rareMETALS.single(score.stat.file, |
| + | cov.file=NULL, |
| + | range="19:11200093-11201275", |
| + | alternative="two.sided", |
| + | ix.gold=1, |
| + | callrate.cutoff=0, |
| + | hwe.cutoff=0) |
| | | |
| == A Simple Tutorial for Using the rareMETALS.gene function == | | == A Simple Tutorial for Using the rareMETALS.gene function == |